Econ 1202

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The question has error, it should be compound annually not monthly, the answer should be 1000 x [(1.045^9-1)/0.045]x 1.045^12= 18319.10

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3072 x (1.004)^72=4094.9493 then minus 3072 and then minus 3072*4.8%*6 (simple interest)

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4.9% p.a. compounded quarterly = 0.01225

   PV = 9736[(1.01225)^-16 + (1.01225)^-32 + (1.01225)^-48 + (1.01225)^-64] 

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use the annuity due formula

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Let x be the monthly payment, r=0.09/12=0.0075

55000*1.0075^68= x[(1.0075^60 -1/0.0075)*1.0075] or there are another way using Geometric  progression 55000*1.0075^68=x[1.0075^60+1.0075^59+.....+1.0075^0]

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Just remember, 2x2 identity matrix is [1 0], then calculating, row is 行 column is 列

                               0 1

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Quite simple question,identity formula: present value of annuity due, let x be the each payment, then x(1-(1+0.096/12)^-60/0.096/12)(1+0.096/12)=22657

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Just use future value of annuity formula. r=0.051/26

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Use the present value of annuity, let x be the payment periodically, n=36

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We can use 8C5*5C3 or 8C5*5C2 , will get same answer 560