Experiment 12: Avogadro's Number
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Experiment 12: Avogadro's Number
CHEMISTRY I
Experiment 12: Avogadro’s number (hand out)
Introduction:
The objective of this experiment is to determine the value of Avogadro’s number and the mole concept via the use of the monolayer experiment.
Experimental data sheet: Attached
Calculations:
1. Area of monolayer
A= 3.14(8.58 cm)І / 4
A= 231 cmІ / 4
A = 57.8 cmІ
2. Molecules of stearic acid in monolayer
57.8 cmІ x 1molecule = 2.8 x 1016 molecules
2.1 x 10-15 cmІ
3. Moles of stearic acid in monolayer
Average drops of stearic acid to make up the monolayer = 6
Average drops of stearic solution in 1 mL = 96
ml of stearic acid in monolayer = 6 / 96 = .0625 ml
Grams of stearic acid in monolayer = .1ml x 1.4 x 10 -4 g ml = 1.4 x 10 -5 g
1.4 x 10 -5 gram stearic acid x 1mol stearic acid = 4.9 x10-8 mol stearic acid
284 g stearic acid
Avogadro’s number = 2.8 x1016 molecules = 5.7 x 10 23 molecules/moles
4.9 x 10 -8 mol
Analysis/Discussion:
Conclusion:
POST QUESTIONS:
1. A. Volume of drops in exactly 1 ml of graduated cylinder.
B. Diameter of water on petri plate.
C. number of drops to make monolayer.
The number of drops to make 1 ml of stearic acid in graduating cylinder was different after 3 trials,
since there is already a 1% error, more trials would yield a lower percent error. Also not reading
the cylinder