The Dehydration of a Bluestone
By: Victor • Essay • 667 Words • April 8, 2010 • 1,218 Views
The Dehydration of a Bluestone
The Dehydration of a Bluestone
February.28.2008
Purpose
• To determine the value of X in CuSO4 • xH2O.
Materials
• Crucible
• Blue Stone
• Bunsen Burner
• Bunsen Lighter
• Test Tube
• Water
• Rheostat
• Clay Triangle
• Electronic Balance
Procedure
A clean crucible was taken and weighed on an electronic balance. The mass was then written down. 2g of bluestone was placed in the crucible and weighed. The mass of the blue solid was written down. The crucible was placed on a clay triangle and was heated by the Bunsen burner. When the blue color disappeared, the crucible was left to cool. After the crucible had cooled, the crucible was placed on the electronic balance to be weighed for its final mass of crucible and anhydrous solid. After the mass was written, a small amount of the anhydrous solid was taken and placed in a test tube. Then a few drops of water were added and the reaction was observed and written down.
Observations
Before
• The solid was in a blue solid crystal form.
During
• As it was heating, the blue solid slowly turned a whitish grayish color.
After
• The blue solid had turned a grayish white color and when water was added back to the anhydrous solid it turned blue again.
• When the water droplets were added the bottom of the test tube felt hot.
Data
Mass of Crucible 14.82 g
Mass of crucible and CuSO4 •xH2O 15.95 g
Mass of Crucible and anhydrous CuSO4 15.52 g
Calculations ------ Molar Mass of Copper Sulphate -> 64.0+32.1+16*4 = 160.1 g/mol
Mass of Crucible 14.82 g No Calculation
Mass of Crucible and Solid 15.95 g No Calculations
Mass of Crucible and Anhydrous Solid 15.52 g No Calculations
Mass of CuSO4 • xH2O 15.95 g – 14.82 g = 1.130 g 1.13 g
Mass of CuSO4 15.52 g – 14.82 g = 0.70 g 0.70 g
Mass of Water Lost 1.13 g – 0.70 g = 0.43 g 0.43 g
# of moles of CuSo4 15.52 – 14.82 = 0.70
0.70/160.1 = 0.044 mol 0.0044 mol
# of moles of Water 0.43 / 18 = 0.024 mol 0.024 mol
Amount of water per mol of CuSO4 0.024 mol / 0.0044 = 5.4 X = 5.4
Discussion
1. How do you know when the copper (2) sulphate has been converted to it anhydrous form?
• When